This sample shows how you can clone a submenu. The "File" submenu is only defined once, but it is replicated several times very easily by just assigning some ID-s and class names accordingly. Here's how it's done: 

      <ul id="menu">
        <li>
          File
          <ul id="the-file-menu">
            ... content of the file menu
          </ul>
        </li>
        ... later ...
        <li class="clones-popup-the-file-menu">
          Clone the file menu
        </li>
      </ul>

As you can see, you only need to add a certain, unique ID to the UL that defines the popup you would like to clone, and on items that should contain a copy of that menu add the class "clones-popup-ID" where ID is the one you assigned to the source UL.

NOTE that you need to pass an additional parameter to DynarchMenu.setup: 

DynarchMenu.setup("menu", { clone: true });

With this parameter on, DynarchMenu will clone the UL and LI contents that initialize the menu so that they can be reused a second time. If you don't pass this parameter then icons and HTML popups will only appear correctly in the first initialized menu.

You can clone a popup as many times you want. You can even use UL-s that aren't direct s of the main menu UL--in other words it doesn't matter where in the document are the UL-s that you wish to clone; DynarchMenu will do the job. To exemplify, following there's a menu that clones the same File popup of the first menu:

Warning: you should be careful not to create "recursive menus". They will work in "lazy" mode (when you pass "lazy: true" at DynarchMenu.setup) but will crash the browser in normal mode. You have been warned.